http://physics.stackexchange.com/questions/41160/jumping-on-earth-versus-jumping-on-the-moon
On the moon the acceleration due to gravity is gm=1.62m/s2. On earth, a person of mass m=80kg manages to jump 1.4m. Find the height this person will reach when jumping on the moon, if the person is wearing a spacesuit with mass m=124kg.
I am a little bit confused as to whether or not the given information regarding mass is actually needed here at all. Assume that v0 is equal in both jumps, and there is no rotational movement, can't we just use the formula for conservation of mechanical energy?
12mv2f+mghf=12mv20+mgh0
And here we can cancel the mass, m since it appears in all terms. So on earth we will have:
ghf=12v20
9.8⋅1.4=12v20
v0=5.2m/s
Then on the moon, since we know v0, we can then find hf:
1.62hf=12⋅(5.2)2
hf=8.3m
Would this not be an acceptable way to solve this? If this is wrong, can anyone please explain why this is wrong conceptually?
